Learn

We’ll continue our theme of list rotation by flipping the problem: given a **sorted** list rotated `k`

times, return the index where the “unrotated” list would begin.

rotated_list = ['c', 'd', 'e', 'f', 'a'] rotation_point(rotated_list) # index 4 # a sorted list would start with 'a' another_rotated_list = [13, 8, 9, 10, 11] rotation_point(rotated_list) # index 1 # a sorted list would start with 8

**Clarifying Questions:**

- Are there constraints on time or space efficiency?
- No! Any solution will do.

- Does the rotation direction matter?
- This won’t affect the return value.

- What if the input isn’t rotated?
- Return 0.

### Instructions

**1.**

Write a function `count_rotations()`

which has one parameter `rotated_list`

.

`count_rotations()`

should return the index where the sorted list would begin.

# Sign up to start coding

By signing up for Codecademy, you agree to Codecademy's Terms of Service & Privacy Policy.